\(b,=\dfrac{12+3x}{2x\left(x+4\right)}=\dfrac{3\left(x+4\right)}{2x\left(x+4\right)}=\dfrac{3}{2x}\\ c,=\dfrac{2x+\left(x+1\right)\left(x+2\right)}{\left(x+2\right)^2}=\dfrac{x^2+7x+2}{x^2+4x+4}\\ d,=\dfrac{3+\left(x-14\right)\left(x+2\right)}{\left(x-2\right)\left(x+2\right)}=\dfrac{x^2-12x-25}{x^2-4}\)


