\(A=\left(x-\dfrac{5}{6}\right)^2+\left(xy-\dfrac{1}{4}\right)^4-2021\ge-2021\\ A_{min}=-2021\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{5}{6}\\xy=\dfrac{1}{4}\end{matrix}\right.\Leftrightarrow y=\dfrac{1}{4}:\dfrac{5}{6}=\dfrac{3}{10}\left(D\right)\)
