Question

Answer 1

Ta có: \(n_{\left(NH_4\right)_2SO_4}=\dfrac{500}{132}=\dfrac{125}{33}\left(mol\right)\)

\(\Rightarrow m_N=\dfrac{125}{33}.14.2\approx106,06\left(g\right)\)

Answer 2

Nguyên tố dinh dưỡng đó là Nito

\(n_{\left(NH_4\right)_2SO_4}=\dfrac{500}{132}=\dfrac{125}{33}\left(mol\right)\\ Tacó:n_N=2n_{\left(NH_4\right)_2SO_4}=\dfrac{250}{33}\left(mol\right)\\ \Rightarrow m_N=\dfrac{250}{33}.14=106,06\left(g\right)\)

=> Chọn C

Answer 3

Chọn C