Question

Answer 1

giúp mink ik

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Answer 2

\(a,\Rightarrow\left|x-\dfrac{3}{5}\right|=\dfrac{1}{3}\Rightarrow\left[{}\begin{matrix}x-\dfrac{3}{5}=\dfrac{1}{3}\\\dfrac{3}{5}-x=\dfrac{1}{3}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{14}{15}\\x=\dfrac{4}{15}\end{matrix}\right.\\ b,\Rightarrow\dfrac{x}{5}=\dfrac{y}{7}=\dfrac{x-y}{5-7}=\dfrac{32}{-2}=-16\\ \Rightarrow\left\{{}\begin{matrix}x=-80\\y=-112\end{matrix}\right.\)