\(a, x=2021-2016=15 b, 2x-2016=64 => x=1040\)
Em tham khảo:
a)
\(x+2006=2021\\ x=2021-2006\\ x=15\)
Vậy \(x=15\)
b)
\(2x-2016=2^4.4\\ 2x-2016=16.4\\ 2x-2016=64\\ 2x=64+2016\\ 2x=2080\\ x=2080:2\\ x=1040\)
Vậy \(x=1040\)
c)
\(3\left(2x+1\right)^3=81\\ \left(2x+1\right)^3=81:3\\ \left(2x+1\right)^3=27\\ =>\left(2x+1\right)^3=3^3\\ =>2x+1=3\\ 2x=3-1\\ 2x=2\\ x=2:2\\ x=1\)
Vậy \(x=1\)
