\(a,=\left(3\dfrac{4}{27}-\dfrac{4}{27}\right)+\left(\dfrac{11}{21}+\dfrac{10}{21}\right)+\dfrac{1}{2}\\ =2\dfrac{4}{27}+1+\dfrac{1}{2}=\dfrac{58}{27}+\dfrac{3}{2}=\dfrac{197}{54}\\ b_1,=6-3\left(-\dfrac{1}{27}\right)-3=3+\dfrac{1}{9}=\dfrac{28}{9}\\ b_2,=\left(-\dfrac{5}{3}\right)\left(16\dfrac{2}{7}-28\dfrac{2}{7}\right)=-\dfrac{5}{3}\cdot\left(-12\dfrac{2}{7}\right)=\dfrac{5}{3}\cdot\dfrac{86}{7}=\dfrac{430}{21}\\ e,=\dfrac{5}{7}\left(13\dfrac{1}{2}-27\dfrac{1}{2}\right)=-14\dfrac{1}{2}\cdot\dfrac{5}{7}=-\dfrac{29}{2}\cdot\dfrac{5}{7}=-\dfrac{145}{14}\)
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