Question

Answer 1

2. 7x(x - 2) - x + 2 = 0

<=> 7x(x - 2) - (x - 2) = 0

<=> (7x - 1)(x - 2) = 0

<=> \(\left[{}\begin{matrix}7x-1=0\\x-2=0\end{matrix}\right.\)

<=> \(\left[{}\begin{matrix}x=\dfrac{1}{7}\\x=2\end{matrix}\right.\)

4. 6x - 1 - 2x(1 - 6x) = 0

<=> (6x - 1) + 2x(6x - 1) = 0

<=> (1 + 2x)(6x - 1) = 0

<=> \(\left[{}\begin{matrix}1+2x=0\\6x-1=0\end{matrix}\right.\)

<=> \(\left[{}\begin{matrix}x=\dfrac{-1}{2}\\x=\dfrac{1}{6}\end{matrix}\right.\)

Answer 2

2) \(\Rightarrow7x\left(x-2\right)-\left(x-2\right)=0\Rightarrow\left(7x-1\right)\left(x-2\right)=0\)

    \(\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{7}\\x=2\end{matrix}\right.\)

4) \(\Rightarrow6x-1+2x\left(6x-1\right)=0\Rightarrow\left(6x-1\right)\left(1+2x\right)=0\)

    \(\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{6}\\x=-\dfrac{1}{2}\end{matrix}\right.\)