Question

Answer 1

1. Gọi CTHH là: \(\overset{\left(V\right)}{P_x}\overset{\left(II\right)}{O_y}\)

Ta có: V . x = II . y

=> \(\dfrac{x}{y}=\dfrac{II}{V}=\dfrac{2}{5}\)

=> CTHH là P₂O₅

2. Gọi CTHH là: \(\overset{\left(I\right)}{Na_a}\overset{\left(I\right)}{\left(NO_3\right)_b}\)

Ta có: I . a = I . b

=> \(\dfrac{a}{b}=\dfrac{I}{I}=\dfrac{1}{1}\)

=> CTHH là: NaNO₃

3. Gọi CTHH là: \(\overset{\left(II\right)}{Zn_m}\overset{\left(III\right)}{\left(PO_4\right)_n}\)

Ta có: II . m = III . n

=> \(\dfrac{m}{n}=\dfrac{III}{II}=\dfrac{3}{2}\)

=> CTHH là: Zn₃(PO₄)₂

Answer 2

1. ta có CTHH: \(P^V_xO_y^{II}\)

\(\rightarrow V.x=II.y\rightarrow\dfrac{x}{y}=\dfrac{II}{V}=\dfrac{2}{5}\rightarrow\left[{}\begin{matrix}x=2\\y=5\end{matrix}\right.\)

\(\rightarrow CTHH:P_2O_5\)

2. ta có CTHH: \(Na^I_x\left(NO_3\right)^I_y\)

\(\rightarrow I.x=I.y\rightarrow\dfrac{x}{y}=\dfrac{I}{I}=\dfrac{1}{1}\rightarrow\left[{}\begin{matrix}x=1\\y=1\end{matrix}\right.\)

\(\rightarrow CTHH:NaNO_3\)

3. ta có CTHH: \(Zn^{II}_x\left(PO_4\right)^{III}_y\)

\(\rightarrow II.x=III.y\rightarrow\dfrac{x}{y}=\dfrac{III}{II}=\dfrac{3}{2}\rightarrow\left[{}\begin{matrix}x=3\\y=2\end{matrix}\right.\)

\(\rightarrow CTHH:Zn_3\left(PO_4\right)_2\)