Gọi CTHH là \(H_xS_yO_Z\)
Ta có \(x=2y;z=2x\Leftrightarrow\left\{{}\begin{matrix}x=2y\\z=4y\end{matrix}\right.\)
\(PTK_{H_xS_yO_z}=x\cdot NTK_H+y\cdot NTK_S+z\cdot NTK_O=2,45\cdot NTK_{Ca}\\ \Leftrightarrow2y\cdot1+y\cdot32+4y\cdot16=2,45\cdot40=98\\ \Leftrightarrow98y=98\Leftrightarrow y=1\Leftrightarrow\left\{{}\begin{matrix}x=2\\z=4\end{matrix}\right.\)
Vậy CTHH cần tìm là \(H_2SO_4\)