Áp dụng t/c dtsbn:
\(\dfrac{b+c-a}{a}=\dfrac{c+a-b}{b}=\dfrac{a+b-c}{c}=\dfrac{a+b+c}{a+b+c}=1\\ \Rightarrow\left\{{}\begin{matrix}b+c-a=a\\c+a-b=b\\a+b-c=c\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}b+c=2a\\a+c=2b\\a+b=2c\end{matrix}\right.\Rightarrow a=b=c\\ \Rightarrow A=\left(1+1\right)\left(1+1\right)\left(1+1\right)=8\)