Bài 1:
\(a,=3\left(x^2-2xy-4z^2+y^2\right)=3\left[\left(x-y\right)^2-4z^2\right]\\ =3\left(x-y-2z\right)\left(x-y+2z\right)\\ b,=x^2-2x-3x+6=\left(x-2\right)\left(x-3\right)\)
Bài 2:
\(a,A=4x^2-xy+2=4\cdot1^2-2\cdot1+2=4\\ b,B=\dfrac{4}{3}x^2-\dfrac{2}{3}xy+\dfrac{8}{9}\\ B=\dfrac{4}{3}\left(-1\right)^2-\dfrac{2}{3}\left(-1\right)\cdot\dfrac{1}{2}+\dfrac{8}{9}=\dfrac{4}{3}+\dfrac{1}{3}+\dfrac{8}{9}=\dfrac{23}{9}\)
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