Question

Answer 1

\(a,\Rightarrow x=\dfrac{3}{5}-\dfrac{1}{2}=\dfrac{1}{10}\\ b,\Rightarrow\left(\dfrac{2}{3}\right)^x=\left(\dfrac{2}{3}\right)^3\Rightarrow x=3\\ c,\Rightarrow2x-\dfrac{1}{2}=\dfrac{3}{2}\Rightarrow2x=2\Rightarrow x=1\\ d,\Rightarrow\left[{}\begin{matrix}x+\dfrac{1}{3}=\dfrac{1}{2}\\x+\dfrac{1}{3}=-\dfrac{1}{2}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{6}\\x=-\dfrac{5}{6}\end{matrix}\right.\)