\(a,=\dfrac{1}{5}-\dfrac{2}{5}=-\dfrac{1}{5}\\ b,=\dfrac{2^5\cdot2^{12}\cdot2^4}{2^{24}}=\dfrac{1}{2^3}=\dfrac{1}{8}\\ c,=\dfrac{19}{17}\left(\dfrac{1}{4}-\dfrac{2}{5}+\dfrac{3}{4}-\dfrac{3}{5}\right)=\dfrac{19}{17}\left(1-1\right)=0\\ d,=9-\dfrac{1}{8}-1=\dfrac{63}{8}\)
