a) Ta có: a⊥AB,b⊥AB
=> a//b
b) Ta có: a//b
\(\Rightarrow\widehat{C_2}=\widehat{D}=120^0\)(đồng vị)
\(\Rightarrow\widehat{C_1}=180^0-\widehat{C_2}=180^0-120^0=60^0\)(kề bù)
c) Ta có: \(\widehat{DCx}+\widehat{yDC}=\dfrac{1}{2}\widehat{D}+\dfrac{1}{2}\widehat{C_2}+\widehat{C_1}=60^0+60^0+60^0=180^0\)
Mà 2 góc này trong cùng phía
=> Cx//Dy
