\(\Rightarrow\dfrac{x}{9}=\dfrac{y}{12}=\dfrac{z}{20}=\dfrac{2x}{18}=\dfrac{3y}{36}=\dfrac{2x-3y+z}{18-36+20}=\dfrac{6}{2}=3\)
\(\Rightarrow\left\{{}\begin{matrix}x=3.9=27\\y=3.12=36\\z=3.20=60\end{matrix}\right.\)
\(\Rightarrow x-2y+z=27-2.36+60=15\)
=> Chọn A