\(1,\\ \left(x+1\right)^2=x^2+2x+1\\ \left(3-a\right)^2=9-6a+a^2\\ \left(x+2\right)\left(x-2\right)=x^2-4\\ \left(2x+1\right)^3=8x^3+12x^2+6x+1\\ \left(x-2\right)^3=x^3-6x^2+12x-8\\ \left(x+2\right)\left(x^2-2x+4\right)=x^3+8\\ \left(x-3\right)\left(x^2+3x+9\right)=x^3-27\\ 2,\\ a,=\left(x-y\right)\left(3-x\right)\\ b,=\left(3x-y\right)\left(3x+y\right)\\ c,=3x\left(4x+2y-x^2\right)\\ d,=\left(x-1-y\right)\left(x-1+y\right)\\ e,=2\left(x-y\right)+b\left(x-y\right)=\left(b+2\right)\left(x-y\right)\\ f,=\left(x+1\right)^2-y^2=\left(x+1-y\right)\left(x+1+y\right)\)
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