\(a,\Leftrightarrow\left(x+3\right)\left(5-2x\right)=0\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=\dfrac{5}{2}\end{matrix}\right.\\ b,\Leftrightarrow\left(3-x\right)^2+\left(3-x\right)=0\\ \Leftrightarrow\left(3-x\right)\left(3-x+1\right)=0\\ \Leftrightarrow\left(3-x\right)\left(4-x\right)=0\Leftrightarrow\left[{}\begin{matrix}x=3\\x=4\end{matrix}\right.\\ c,\Leftrightarrow\left(x+4-4\right)\left(x+4+4\right)=0\\ \Leftrightarrow x\left(x+8\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-8\end{matrix}\right.\\ d,\Leftrightarrow\left(x-5\right)^2=0\Leftrightarrow x-5=0\Leftrightarrow x=5\)
a) \(\Rightarrow\left(x+3\right)\left(5-2x\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=-3\\x=\dfrac{5}{2}\end{matrix}\right.\)
b) \(\Rightarrow\left(x-3\right)-\left(x-3\right)^2=0\)
\(\Rightarrow\left(x-3\right)\left(4-x\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=3\\x=4\end{matrix}\right.\)
c) \(\Rightarrow\left(x+4-4\right)\left(x+4+4\right)=0\)
\(\Rightarrow x\left(x+8\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x=-8\end{matrix}\right.\)
d) \(\Rightarrow x^2-10x+25=0\Rightarrow\left(x-5\right)^2=0\)
\(\Rightarrow x=5\)
