Bài 3:
a) Ta có: \(\left[H^+\right]=0,005\cdot2=0,01\left(M\right)\) \(\Rightarrow pH=-log\left(0,01\right)=2\)
b) Ta có: \(\left[OH^-\right]=0,0005\cdot2=10^{-3}\left(M\right)\) \(\Rightarrow pH=14+log\left(10^{-3}\right)=11\)
c) Ta có: \(n_{H^+}=0,05\cdot0,1\cdot2+0,05\cdot0,05\cdot2=0,015\left(mol\right)\)
\(\Rightarrow\left[H^+\right]=\dfrac{0,015}{0,1}=0,15\left(M\right)\) \(\Rightarrow pH=-log\left(0,15\right)\approx0,82\)
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