\(=\dfrac{5}{2}\left(\dfrac{2}{1\times3}+\dfrac{2}{3\times5}+...+\dfrac{2}{133\times135}\right)\\ =\dfrac{5}{2}\left(1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+...+\dfrac{1}{133}-\dfrac{1}{135}\right)\\ =\dfrac{5}{2}\left(1-\dfrac{1}{135}\right)=\dfrac{5}{2}\times\dfrac{134}{135}=\dfrac{67}{27}\)
4 và 5