\(a,\Rightarrow\left(x-1\right)\left(3x+1\right)=0\Rightarrow\left[{}\begin{matrix}x=1\\x=-\dfrac{1}{3}\end{matrix}\right.\\ b,\Rightarrow\left(2x-1-5\right)\left(2x-1+5\right)=0\\ \Rightarrow\left(2x-6\right)\left(2x+4\right)=0\\ \Rightarrow4\left(x-3\right)\left(x+2\right)=0\Rightarrow\left[{}\begin{matrix}x=3\\x=-2\end{matrix}\right.\\ c,\Rightarrow\left(x+3\right)\left(x^2-3x+9\right)-\left(x+3\right)\left(x+9\right)=0\\ \Rightarrow\left(x+3\right)\left(x^2-3x+9-x-9\right)=0\\ \Rightarrow\left(x+3\right)\left(x^2-4x\right)=0\\ \Rightarrow x\left(x-4\right)\left(x+3\right)=0\Rightarrow\left[{}\begin{matrix}x=0\\x=4\\x=-3\end{matrix}\right.\\ d,\Rightarrow x^3-8=-2x^2+8+5x-10\\ \Rightarrow x^3+2x^2-5x-10=0\\ \Rightarrow x^2\left(x+2\right)-5\left(x+2\right)=0\\ \Rightarrow\left(x+2\right)\left(x^2-5\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=-2\\x=\sqrt{5}\\x=-\sqrt{5}\end{matrix}\right.\)
