Áp dụng t/c dtsbn:
\(\dfrac{x-1}{2}=\dfrac{y+3}{4}=\dfrac{z-5}{6}=\dfrac{-3\left(x-1\right)}{-6}=\dfrac{-4\left(y+3\right)}{-16}=\dfrac{5\left(z-5\right)}{30}=\dfrac{-3x+3-4x-12+5z-25}{-6-16+30}=\dfrac{16}{8}=2\\ \Rightarrow\left\{{}\begin{matrix}x-1=4\\y+3=8\\z-5=12\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=5\\y=5\\z=17\end{matrix}\right.\)
