Question

Answer 1

e) \(3x-2y\Rightarrow\dfrac{x}{2}=\dfrac{y}{3}\)

Áp dụng t/c dtsbn:

\(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{2x}{4}=\dfrac{3y}{9}=\dfrac{2x+3y}{4+9}=\dfrac{-65}{13}=-5\)

\(\Rightarrow\left\{{}\begin{matrix}x=\left(-5\right).2=-10\\y=\left(-5\right).3=-15\end{matrix}\right.\)

f) Áp dụng t/c dtsbn:

\(\dfrac{x}{4}=\dfrac{y}{3}=\dfrac{z}{2}=\dfrac{x+y+z}{4+3+2}=\dfrac{81}{9}=9\)

\(\Rightarrow\left\{{}\begin{matrix}x=9.4=36\\y=8.3=27\\z=9.2=18\end{matrix}\right.\)