Đặt \(\dfrac{x}{3}=\dfrac{y}{2}=\dfrac{z}{4}=k\Rightarrow x=3k;y=2k;z=4k\)
\(x^2+2y^2-z^2=1\\ \Rightarrow9k^2+8k^2-16k^2=1\\ \Rightarrow k^2=1\\ \Rightarrow\left[{}\begin{matrix}k=1\\k=-1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3;y=2;z=4\\x=-3;y=-2;z=-4\end{matrix}\right.\)