\(1,ĐK:x\ge\dfrac{3}{2}\\ PT\Leftrightarrow2x-3=x^2-2x+1\\ \Leftrightarrow x^2-4x+4=0\\ \Leftrightarrow x=2\left(tm\right)\\ 2,ĐK:x\ge1\\ PT\Leftrightarrow2x+3=x^2-2x+1\\ \Leftrightarrow x^2-4x-2=0\\ \Delta=16+8=24\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{4-2\sqrt{6}}{2}=2-\sqrt{6}\left(ktm\right)\\x=\dfrac{4+2\sqrt{6}}{2}=2+\sqrt{6}\left(tm\right)\end{matrix}\right.\\ \Leftrightarrow x=2+\sqrt{6}\)
\(3,ĐK:x\ge1\\ PT\Leftrightarrow x+3=x^2-2x+1\\ \Leftrightarrow x^2-3x-2=0\\ \Delta=9+8=17\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3-\sqrt{17}}{2}\left(ktm\right)\\x=\dfrac{3+\sqrt{17}}{2}\left(tm\right)\end{matrix}\right.\Leftrightarrow x=\dfrac{3+\sqrt{17}}{2}\\ 4,ĐK:x\ge1\\ PT\Leftrightarrow x+2=x^2-2x+1\\ \Leftrightarrow x^2-3x-1=0\\ \Delta=9+4=13\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3+\sqrt{13}}{2}\left(tm\right)\\x=\dfrac{3-\sqrt{13}}{2}\left(ktm\right)\end{matrix}\right.\Leftrightarrow x=\dfrac{3+\sqrt{13}}{2}\)
