Question

Answer 1

PTHH: \(HCl+AgNO_3\rightarrow HNO_3+AgCl\downarrow\)

Hiện tượng: Xuất hiện kết tủa trắng

Ta có: \(n_{AgNO_3}=\dfrac{170\cdot10\%}{170}=0,1\left(mol\right)=n_{HCl}=n_{HNO_3}=n_{AgCl}\) 

\(\Rightarrow\left\{{}\begin{matrix}m_{AgCl}=0,1\cdot143,5=14,35\left(g\right)\\m_{HNO_3}=0,1\cdot63=6,3\left(g\right)\\V_{ddHCl}=\dfrac{0,1}{1}=0,1\left(l\right)=100\left(ml\right)\\\end{matrix}\right.\)

Mặt khác: \(m_{ddHCl}=100\cdot1,05=105\left(g\right)\)

\(\Rightarrow m_{dd}=m_{ddHCl}+m_{ddAgNO_3}-m_{AgCl}=260,65\left(g\right)\)

\(\Rightarrow C\%_{HNO_3}=\dfrac{6,3}{260,65}\cdot100\%\approx2,42\%\)