\(1,\\ \left(3x^3+10x^2+14x+3\right):\left(3x+4\right)\\ =\left(3x^3+4x^2+6x^2+8x+6x+8-5\right):\left(3x+4\right)\\ =\left[\left(3x+4\right)\left(x^2+2x+2\right)-5\right]:\left(3x+4\right)\\ =x^2+2x+2\left(dư-5\right)\)
\(2,f\left(x\right)⋮g\left(x\right)\\ \Leftrightarrow x^3-3x^2+5x+m-2=\left(x-2\right)\cdot a\left(x\right)\)
Thay \(x=2\Leftrightarrow8-3\cdot4+5\cdot2+m-2=0\)
\(\Leftrightarrow8-12+10+m-2=0\\ \Leftrightarrow m=-4\)
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