\(B=\dfrac{2^3}{3.5}+\dfrac{2^3}{5.7}+...+\dfrac{2^3}{101.103}\)
\(=2^2\left(\dfrac{2}{3.5}+\dfrac{2}{5.7}+...+\dfrac{2}{101.102}\right)\)
\(=2^2\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{101}-\dfrac{1}{103}\right)\)
\(=2^2\left(1-\dfrac{1}{103}\right)=2^2.\dfrac{102}{103}=\dfrac{408}{103}\)
