Question

Answer 1

Bai 1 : 

a) Chat khi : \(Na_2CO_3+HCl\rightarrow NaCl+CO_2+H_2O\)

b) Chat ket tua : \(BaCl_2+H_2SO_4\rightarrow BaSO_4+2HCl\)

c) Kim loai moi : \(CuSO_4+Fe\rightarrow FeSO_4+Cu\)

 Chuc ban hoc tot

Answer 2

Bai 5 : 

\(n_{CO2}=\dfrac{4,48}{22,4}=0,2\left(mol\right)\)

Pt : \(Na_2SO_3+2HCl\rightarrow2NaCl+SO_2+H_2O|\)

            1                2            2           1            1

          0,2            0,4           0,4         0,2

a) \(n_{Na2SO3}=\dfrac{0,2.1}{1}=0,2\left(mol\right)\)

\(m_{Na2SO3}=0,2.126=25,2\left(g\right)\)

\(m_{NaCl}=36,9-25,2=11,7\left(g\right)\) 

⁰/₀Na₂SO₃ = \(\dfrac{25,2.100}{36,9}=68,29\)⁰/₀

⁰₀NaCl = \(\dfrac{11,7.100}{36,9}=31,71\)⁰/₀

b) \(n_{HCl}=\dfrac{0,2.2}{1}=0,4\left(mol\right)\)

500ml = 0,5l

\(C_{M_{ddHCl}}=\dfrac{0,4}{0,5}=0,8\left(M\right)\)

c) \(n_{NaCl}=\dfrac{0,2.2}{1}=0,4\left(mol\right)\)

\(C_{M_{NaCl}}=\dfrac{0,4}{0,5}=0,8\left(M\right)\)

 Chuc ban hoc tot