Question

Answer 1

Answer 2

b) Ta có: \(\dfrac{x}{8}=\dfrac{2x}{16}\)

Áp dụng tính chất của DS bằng nhau, ta có: \(\dfrac{2x+y-z}{16+5-6}=\dfrac{-30}{15}=-2\)

\(\dfrac{x}{8}=-2\Rightarrow x=-16\)

\(\dfrac{y}{5}=-2\Rightarrow y=-10\)

\(\dfrac{z}{6}=-2\Rightarrow z=-12\)

 

Answer 3

=>\(\dfrac{2x}{16}=\dfrac{y}{5}=\dfrac{z}{6}=\dfrac{2x+y-z}{15}=\dfrac{-30}{15}=-2\)
x=-16
y=-10
z=-12