Question

Answer 1

\(1,=\left(2x-3-2x-3\right)\left(2x-3+2x+3\right)=-24x\\ 2,=\left(x+3-2x+5\right)\left(x+3+2x-5\right)\\ =\left(8-x\right)\left(3x-2\right)=-3x^2+26x-16\\ 3,=\left(x-2-x+3\right)\left(x-2+x-3\right)=2x-5\\ 4,=\left(2x-1-x-2\right)\left(2x-1+x+2\right)\\ =\left(x-3\right)\left(3x+1\right)=3x^2-8x-3\\ 5,=x^3+3x^2y+3xy^2+y^3-x^3+3x^2y-3xy^2+y^3-2y^3\\ =6x^2y\\ 6,=\left(x+y+z-x-y\right)^2=z^2\\ 7,=27x^3-y^3\\ 8,=x^3+64\)

Answer 2

1)
=(2x-3-2x-3)(2x-3+2x+3)
=-9 . 4x
2)
=(x+3-2x+5)(x+3+2x-5)
=(-x+8)(3x-2)