Question

Answer 1

PTHH: \(2KClO_3\xrightarrow[MnO_2]{t^o}2KCl+3O_2\uparrow\)

            \(C_2H_4+3O_2\xrightarrow[]{t^o}2CO_2+2H_2O\)

            \(C_3H_8+5O_2\xrightarrow[]{t^o}3CO_2+4H_2O\)

Ta có: \(\left\{{}\begin{matrix}n_{C_2H_4}=\dfrac{6,72}{22,4}=0,3\left(mol\right)\\n_{C_3H_8}=\dfrac{4,48}{22,4}=0,2\left(mol\right)\end{matrix}\right.\) \(\Rightarrow n_{O_2}=3n_{C_2H_4}+5n_{C_3H_8}=1,9\left(mol\right)\)

\(\Rightarrow n_{KClO_3}=\dfrac{19}{15}\left(mol\right)\) \(\Rightarrow m_{KClO_3}=\dfrac{19}{15}\cdot122,5\approx155,17\left(g\right)\)