1) \(\dfrac{x}{3}=\dfrac{y}{4}=\dfrac{x+y}{3+4}=\dfrac{14}{7}=2\)
\(\Rightarrow\left\{{}\begin{matrix}x=2.3=6\\y=2.4=8\end{matrix}\right.\)
2) \(ĐK:x\ne0\)
\(\dfrac{2x+1}{5}=\dfrac{3y-2}{7}=\dfrac{2x+1+3y-2}{5+7}=\dfrac{2x+3y-1}{12}\)
Mà \(\dfrac{2x+1}{5}=\dfrac{3y-2}{7}=\dfrac{2x+3y-1}{6x}\)
\(\Rightarrow6x=12\Rightarrow x=2\left(tm\right)\)
