Question

Answer 1

Do \(\left|x-2,3\right|\ge0;\left|3,5-x\right|\ge0\)

\(\Rightarrow\left\{{}\begin{matrix}x-2,3=0\\3,5-x=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=2,3\\x=3,5\end{matrix}\right.\Rightarrow x\in\varnothing\)

Answer 2

\(\left|x-2,3\right|+\left|3,5-x\right|=0\)

\(\left|x-2,3\right|+\left|3,5-x\right|\) ≥\(\left|x-2,3+3,5-x\right|\)\(=1,2\)

⇔\(\left(x-2,3\right)\left(3,5-x\right)\) ≥\(0\)

⇔\(2,3\)≤x≤\(3,5\)