Question

Answer 1

\(a,\left\{{}\begin{matrix}\widehat{MOE}=\widehat{OMN}=45^0\left(so.le.trong.do.OE//MN\right)\\\widehat{EOP}+\widehat{OPQ}=180^0\left(2.góc.TCP\right)\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}\widehat{MOE}=45^0\\\widehat{EOP}=50^0\end{matrix}\right.\)

\(\widehat{MOP}=\widehat{MOE}+\widehat{EOP}=45^0+50^0=95^0\)

\(b,\widehat{MOE}=45^0\ne47,5^0=\dfrac{\widehat{MOP}}{2}\)

Vậy OE không phải là p/g \(\widehat{MOP}\)