\(1,\\ a,A=8x^3-1-\left(8x^3+1\right)+3x=3x-2\\ b,x=-1\Leftrightarrow A=-3-2=-5\\ c,A=0\Leftrightarrow3x-2=0\Leftrightarrow x=\dfrac{2}{3}\\ 2,\\ a,=3x\left(x-3y\right)-6\left(x-3y\right)=3\left(x-2\right)\left(x-3y\right)\\ b,=\left(3x-4\right)\left(3x+4\right)+\left(3x-2\right)\left(3x+4\right)\\ =\left(3x+4\right)\left(3x-4+3x-2\right)\\ =\left(3x+4\right)\left(6x-6\right)=6\left(x-1\right)\left(3x+4\right)\\ c,=x^2-x-3x+3=\left(x-1\right)\left(x-3\right)\)
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