Bài 4: Đề hỏi gì đó em?
BTVN:
\(n_{Zn}=\dfrac{6,5}{65}=0,1\left(mol\right)\\ n_{HCl}=\dfrac{3,65}{36,5}=0,1\left(mol\right)\\a. Zn+2HCl\rightarrow ZnCl_2+H_2\\ b.Vì:\dfrac{0,1}{2}< \dfrac{0,1}{1}\Rightarrow Zndư\\ \Rightarrow n_{Zn\left(dư\right)}=0,1-\dfrac{0,1}{2}=0,05\left(mol\right)\\ \Rightarrow m_{Zn\left(dư\right)}=0,05.65=3,25\left(g\right)\)