\(\dfrac{x}{x^2+2x+1}=\dfrac{x}{\left(x+1\right)^2}=\dfrac{5x\left(x-1\right)}{5\left(x-1\right)\left(x+1\right)^2}=\dfrac{5x^2-5x}{5\left(x-1\right)\left(x+1\right)^2}\)
\(\dfrac{3}{5x^2-5}=\dfrac{3}{5\left(x^2-1\right)}=\dfrac{3}{5\left(x-1\right)\left(x+1\right)}=\dfrac{3x+3}{5\left(x-1\right)\left(x+1\right)^2}\)
\(\dfrac{x}{x^2+2x+1}\Leftrightarrow\dfrac{x}{\left(x+1\right)^2}\Leftrightarrow\dfrac{5x\left(x-1\right)}{5\left(x-1\right)\left(x+1\right)^2}\)
\(\dfrac{3}{5x^2-5}\Leftrightarrow\dfrac{3}{5\left(x^2-1\right)}\Leftrightarrow\dfrac{3\left(x+1\right)}{5\left(x-1\right)\left(x+1\right)^2}\)
