\(a)\)
\(Zn + H_2SO_4 \rightarrow ZnSO_4 + H_2 \)
\(ZnO + H_2SO_4 \rightarrow ZnSO_4 + H_2O\)
\(b)\)
\(n_{H_2}= \dfrac{3,36}{22,4} =0,15 mol\)
\(Theo PTHH: n_{Zn} = n_{H_2} = 0,15 mol\)
\(\Rightarrow m_{Zn}= 0,15 . 65 =9,75 g\)
\(\Rightarrow m_{ZnO}= 13,8 - 9,75 =4,05 g\)
\(c)\)
\(Theo 2 PTHH: \)
\(n_{H_2SO_4}= n_{Zn} + n_{ZnO}=0,15 + 0,05 = 0,2 mol\)
\(\Rightarrow m_{H_2SO_4}= 0,2 . 98 = 19,6 g\)
\(\Rightarrow m_{dd H_2SO_4} = \dfrac{19,6 . 100}{7,84}= 250g\)
\(d)\)
\(Theo 2 PTHH: \)
\(n_{ZnSO_4}= n_{Zn} + n_{ZnO} = 0,2 mol\)
\(\Rightarrow m_{ZnSO_4}= 0,2 . 161= 32,2 g\)
\(n_{H2}=\dfrac{3,36}{22,4}=0,15\left(mol\right)\)
a) Pt : \(Zn+H_2SO_4\rightarrow ZnSO_4+H_2|\)
1 1 1 1
0,15 0,15 0,15 0,15
\(ZnO+H_2SO_4\rightarrow ZnSO_4+H_2O|\)
1 1 1 1
0,05 0,05 0,05
b) \(n_{Zn}=\dfrac{0,15.1}{1}=0,15\left(mol\right)\)
\(m_{Zn}=0,15.65=9,75\left(g\right)\)
\(m_{ZnO}=13,8-9,75=4,05\left(g\right)\)
c) Có : \(m_{ZnO}=4,05\left(g\right)\)
\(n_{ZnO}=\dfrac{4,05}{81}=0,05\left(mol\right)\)
\(n_{H2SO4\left(tổng\right)}=0,15+0,05=0,2\left(mol\right)\)
\(m_{H2SO4}=0,2.98=19,6\left(g\right)\)
\(m_{ddH2SO4}=\dfrac{19,6.100}{7,84}=250\left(g\right)\)
d) \(n_{ZnSO4\left(tổng\right)}=0,15+0,05=0,2\left(mol\right)\)
⇒ \(m_{ZnSO4}=0,2.161=32,2\left(g\right)\)
\(m_{ddspu}=13,8+250-\left(0,15.2\right)=263,5\left(g\right)\)
\(C_{ZnSO4}=\dfrac{32,2.100}{263,5}=12,22\)0/0
Chúc bạn học tốt
