Lời giải:
$\widehat{A}=3\widehat{D}$
$\widehat{A}+\widehat{D}=180^0$ (hai góc trong cùng phía)
$\Rightarrow 3\widehat{D}+\widehat{D}=180^0$
$\Leftrightarrow 4\widehat{D}=180^0$
$\Leftrightarrow \widehat{D}=45^0$
$\widehat{A}=3\widehat{D}=135^0$
Mặt khác:
$\widehat{B}+\widehat{C}=180^0$ (hai góc trong cùng phía)
$\widehat{B}-\widehat{C}=30^0$
$\Rightarrow \widehat{B}=\frac{180^0+30^0}{2}=105^0$
$\widehat{C}=\widehat{B}-30^0=105^0-30^0=75^0$


