\(P=\left(x^2+y^2+1-2x-2y+4xy\right)+\left(4y^2-4y+1\right)+2019\\ =\left(x+y-1\right)^2+\left(2y-1\right)^2+2019\ge2019\)
Dấu \("="\Leftrightarrow\left\{{}\begin{matrix}x=1-y\\y=-\dfrac{1}{2}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{3}{2}\\y=-\dfrac{1}{2}\end{matrix}\right.\)