Question

Answer 1

a,A=\(3\dfrac{1}{7}-\left(5.0,05+\dfrac{22}{7}\right)-\left(4+0,75\right)=3+\dfrac{1}{7}-\left(5.\dfrac{1}{20}+\dfrac{22}{7}\right)-\left(4+\dfrac{3}{4}\right)=\left(3-4\right)+\left(\dfrac{1}{7}-\dfrac{22}{7}\right)-\left(\dfrac{1}{4}+\dfrac{3}{4}\right)=-1+\left(-3\right)-1=-5\)

Answer 2

b,\(B=\dfrac{\left(-1\right)^{2018}.\left(\dfrac{2}{5}\right)^3.\left(\dfrac{15}{4}\right)^2}{\dfrac{15^2}{2^4}.\left(\dfrac{2}{5}\right)^3}=\dfrac{\left(-1\right)^{2018}.\dfrac{15^2}{4^2}}{\dfrac{15^2}{4^2}}=\left(-1\right)^{2018}=1\)