Câu 5:
\(m_{CO_2}=n_{CO_2}.M_{CO_2}=0,5.44=22\left(g\right)\)
-> CHỌN C
Câu 6:
\(n_{H_2SO_4}=\dfrac{m_{H_2SO_4}}{M_{H_2SO_4}}=\dfrac{14,7}{98}=0,15\left(mol\right)\)
-> Chọn C
Câu 7:
\(V_{O_2\left(đktc\right)}=22,4.n_{O_2}=22,4.0,65=14,56\left(l\right)\)
-> Chọn D
Câu 8:
\(n_{SO_2}=\dfrac{V_{O_2\left(đktc\right)}}{22,4}=\dfrac{26,88}{22,4}=1,2\left(mol\right)\\ \rightarrow m_{SO_2}=n_{SO_2}.M_{SO_2}=1,2.64=76,8\left(g\right)\)
=> Chọn B
Câu 9:
\(n_{CH_4}=\dfrac{m_{CH_4}}{M_{CH_4}}=\dfrac{12}{16}=0,75\left(mol\right)\\ V_{CH_4\left(đktc\right)}=n_{CH_4}.22,4=0,75.22,4=16,8\left(l\right)\)
=> Chọn B
Câu 10:
\(n_{Al}=\dfrac{m_{Al}}{M_{Al}}=\dfrac{12,15}{27}=0,45\left(mol\right)\)
Số nguyên tử Al có trong 12,15 gam Al là:
\(0,45.6.10^{23}=2,7.10^{23}\left(nguyên.tử\right)\)
=> Chọn A
