Ta có: Mx//Aa => \(\widehat{AMx}=\widehat{MAa}=40^0\)( 2 góc so le trong)(1)
Ta có Mx//Aa => \(\widehat{BMx}=\widehat{MBb}=50^0\)( 2 góc so le trong)(2)
Từ (1),(2) \(\Rightarrow\widehat{AMB}=\widehat{AMx}+\widehat{BMx}=40^0+50^0=90^0\Rightarrow MA\perp MB\)