\(2a^2\left(1-4a\right)+\left(2a-1\right)^3=2a^2-8a^3+8a^2-12a^2+6a-1=-10a^2+6a-1=-10\left(a^2-2.\dfrac{3}{10}.a+\dfrac{9}{100}\right)+\dfrac{9}{10}-1=-10\left(a-\dfrac{3}{10}\right)^2-\dfrac{1}{10}\le-10.0-\dfrac{1}{10}=-\dfrac{1}{10}\)Dấu "=" xảy ra \(\Leftrightarrow a=\dfrac{3}{10}\)

