Question

Answer 1

chuyển mạch trên về mạch sao

\(=>x=\dfrac{R2.Rv}{R2+Rv+R4}=\dfrac{9.150}{9+150+7}=\dfrac{675}{83}\left(ôm\right)\)

\(=>y=\dfrac{R2.R4}{R2+R4+Rv}=\dfrac{9.7}{9+7+150}=\dfrac{63}{166}\left(ôm\right)\)

\(=>z=\dfrac{R4.Rv}{R4+R5+Rv}=\dfrac{150.7}{150+7+9}=\dfrac{525}{83}\left(ôm\right)\)

\(=>Rtd=\dfrac{\left(R1+x\right)\left(R3+z\right)}{R1+R3+x+z}+y=\dfrac{\left(2+\dfrac{675}{83}\right)\left(3+\dfrac{525}{83}\right)}{2+3+\dfrac{1200}{83}}\)

\(+\dfrac{63}{166}=5,2\left(ôm\right)\)

(kết quả xấu thế nhờ)