Question

Answer 1

Ta có: \(m_{ddH_2SO_4}=1000\cdot1,84=1840\left(g\right)\) \(\Rightarrow m_{H_2SO_4}=1840\cdot98\%=1803,2\left(g\right)\)

\(\Rightarrow m_{ddH_2SO_4\left(10\%\right)}=\dfrac{1803,2}{10\%}=18032\left(g\right)\)

\(\Rightarrow m_{H_2O\left(thêm\right)}=18032-1840=16192\left(g\right)\)

\(\Rightarrow V_{H_2O}=16,192\left(l\right)\)

   Chọn C