Question

Answer 1

\(\left(x+\dfrac{1}{3}\right)^2-10\left(x+\dfrac{1}{3}\right)+9=0\)

\(\Leftrightarrow\left(x+\dfrac{1}{3}\right)^2-10\left(x+\dfrac{1}{3}\right)+25-16=0\)

\(\Leftrightarrow\left(x-\dfrac{14}{3}\right)^2=16\)

\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{14}{3}=4\\x-\dfrac{14}{3}=-4\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{26}{3}\\x=\dfrac{2}{3}\end{matrix}\right.\)

Vậy

Answer 2

\(\left(x+\dfrac{1}{3}\right)^2-10\left(x+\dfrac{1}{3}\right)+9=0\)