PTHH: \(CH_4+2O_2\xrightarrow[]{t^o}CO_2+2H_2O\)
\(2C_4H_{10}+13O_2\xrightarrow[]{t^o}8CO_2+10H_2O\)
Tỉ lệ về thể tích cũng là tỉ lệ về số mol \(\Rightarrow\dfrac{n_{CH_4}}{n_{C_4H_{10}}}=\dfrac{1}{2}\)
Mà \(n_{CH_4}+n_{C_4H_{1o}}=\dfrac{6,72}{22,4}=0,3\left(mol\right)\) \(\Rightarrow\left\{{}\begin{matrix}n_{CH_4}=0,1\left(mol\right)\\n_{C_4H_{10}}=0,2\left(mol\right)\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}n_{O_2}=1,5\left(mol\right)\\n_{CO_2}=0,9\left(mol\right)\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}V_{kk}=\dfrac{1,5\cdot22,4}{20\%}=168\left(l\right)\\V_{CO_2}=0,9\cdot22,4=20,16\left(l\right)\end{matrix}\right.\)
