\(A=143^2-2.53.143+53^2=\left(143-53\right)^2=90^2=8100\)
\(B=3\left(x^2+\dfrac{5}{3}x-\dfrac{1}{3}\right)=3\left(x^2+2.\dfrac{5}{6}x+\dfrac{25}{36}-\dfrac{37}{36}\right)\)
\(=3\left[\left(x+\dfrac{5}{6}\right)^2-\dfrac{37}{36}\right]=3\left(x+\dfrac{5}{6}\right)^2-\dfrac{37}{12}\ge-\dfrac{37}{12}\)
\(B_{min}=-\dfrac{37}{12}\) khi \(x=-\dfrac{5}{6}\)

