Câu 2: Al -> Al2O3 -> AlCl3 -> Al(OH)3 -> Al2(SO4)3
(1) 4 Al +3 O2 -to-> 2 Al2O3
(2) Al2O3 + 6 HCl -> 2 AlCl3 + 3 H2O
(3) AlCl3 + 3 KOH -> Al(OH)3 + 3 KCl
(4) 2 Al(OH)3 + 3 H2SO4 -> Al2(SO4)3 +6 H2O
Bài 1: Đặt nCuO=a(mol); nZnO=b(mol) (a,b>0)
a) PTHH: CuO +2 HCl -> CuCl2 + H2O
a______________2a___amol)
ZnO +2 HCl -> ZnCl2 + H2O
b____2b_____b(mol)
b) Ta có hpt:
\(\left\{{}\begin{matrix}80a+81b=12,1\\2a+2b=0,15.2=0,3\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}a=0,05\\b=0,1\end{matrix}\right.\)
=> mCuO=0,05.80=4(g)
=>%mCuO=(4/12,1).100=33,058%
=>%mZnO= 66,942%
a)
$CuO + 2HCl \to CuCl_2 + H_2O$
$ZnO + 2HCl \to ZnCl_2 + H_2O$
b)
Gọi $n_{CuO} = a(mol) ; n_{ZnO} = b(mol)$
Ta có :
$80a + 81b = 12,1$
$n_{HCl} = 2a + 2b = 0,15.2 = 0,3$
Suy ra a = 0,05 ; b = 0,1
$\%m_{CuO} = \dfrac{0,05.80}{12,1}.100\% = 33,06\%$
$\%m_{ZnO} = 100\% -33,06\% = 66,94\%$
